Assuming the number of defects in a part isλ= 5, What is the expected number of defects in a part? What is the probability of two defects?
Up to two defects?
Expected number of defects = 5
Probability of two defects = P{x = 2, X = 5) = e-552/2! = 0.0842 Probability of up to two defects = P(0, 1,2) = e-5(l + 5 + 25/2) = 0.12
Assuming that the number of defects in a production line during a single hour is \ = 4. What is the probability that six defects will occur in that hour?
P(x = 6, λ = 4) = e-446/6! = 0.1042
Assuming the probability of obtaining a defective product is 0.01, what is the probability of obtaining at least three defective products out of a lot of 100, using binomial and Poisson distributions?
For binomial distribution:
The result of the Poisson distribution is in good agreement with the value of the binomial distribution for small p and large n, but much easier to compute.
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